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Truth teller and lie detector problems

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The key idea of the truth teller identification in competitive exams is to test one's logical ability to answer questions and its usage is increasing day by day, It is the way to test your ability to identify the level truth or lie from many given inferences to draw some conclusion.From the given set of statements by few persons, has to draw a conclusion. Truth teller, Lie Detector.    Types of people in Truth teller and lie detector problems: Liar : A person who always lie. Truth Teller :A person who always says the truth. Alternator: A person whose answers always alters in a step fashion(example: if he say 3 statements, his statements' truthness can be either T, F, T or F, T, F)

Simple Interest aptitude tricks

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Well we are all aware of calculating simple interest in our regular life and perhaps many solve this on the go,even though this post is for some one who is trying to figure out how to calculate simple interest for a loan lend or borrowed. Terms: Simple Interest(SI):Cash to be paid for using other's money. Principal(P): Amount lend or Amount borrowed.

Remainders in math expressions

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A Remainder is the portion is left unused after doing some process,In this context remainder is a number which is left when a number is divided by another number. In the basic levels of our education,we learn how to find remainders of normal maths expressions like Remainder("5",4)=1 but what if the question is asked in the form of Remainder( "19*19*17*21*9" ,"5") calculation part requires more time than the time we get to solve the same in the exam if we follow traditional methods. Divisor A number by which another number to be divided.

Profit loss and discount problems

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One of the important roles of an organization is to ensure the overall performance based on profit as it is the only factor for organization's sustainability.so profit and loss problems have a great role in quantative aptitude. In general,profit can be defined as the financial gain and loss can be defined as the amount lost. There are few more terms which one should learn  Cost Price(C.P): Amount incurred for purchasing/manufacturing the product. Selling Price(S.P): Gained amount in process of selling the product.

Units place in math expression

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Many exams try to make you feel that you cannot solve the problem by making question as big as possible like units place of (186937)^178909 but solving this problem is as simple as solving 9%4 Before solving these kind of problems, understand the great concept called Cyclicity of numbers which states that any digit when multiplied by itself repeatedly, generates a cycle of digits. points to remember: Only units place will be responsible for generating units place Every number after applying successive multiplications,repeats the cycle of digits. So try to figure out a common series in powers of digits for example units(3)=3,units(3*3)=9,units(9*3)=7,units(7*3)=1,units(1*3)=3(we get a cycle of multiplication) Number      powers                         Series/cycle(units place of powers column) [cyclicity of number] 2                 2,4,8,16,32                   2,4,8,6                    [4] 3                 3,9,27,81,243               3,9,7,1              

Direction and distance

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In the direction based problems, we should generally determine the direction or distance if a person travels in a path with many lefts or rights and turns in a certain direction. Basic things which we need to keep in our mind while solving direction based problems includes the direction compass. If we measure the angles between directions, the angle between two successive directions is 90 degrees.

Pipes and cistern problems

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In the pipes and cistern problems, the majority of the problems deals with Inflow,outflow,current capacity, full tank,empty tank. There will be few inlets connected to a dam or tank through which water enters into dam or tank and outlet through which water exits the tank or dam. cistern: A tank to store water. Important points. If pipe can fill the tank in 'x' hours then rate of flow is 1/x(1/x portion of tank gets filled in 1 hour)(when we divide the tank into x parts,one part gets filled in a unit of time) If pipe can empty the tank in 'y' hours then emptying rate is 1/y(1/y portion of tank gets emptied in 1 hour)

Finding L.C.M and H.C.F of two numbers and applications

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L.C.M can be defined as Least Common Multiple of all the numbers. H.C.F can be defined as Highest Common Factor of all the numbers. Important formulae: LCM*HCF=product of the numbers. If any number is factor of other then LCM is bigger one and HCF is the other. In general to find LCM,we need to write all the multiples of given numbers and find common number in the series similarly to find HCF of few given numbers,we need to find all factors of given numbers and identify big such factor common for both the numbers but this is a time taking process so we are here for you with some other trick. First let us know about the traditional methods to find LCM,HCF. In traditional method,to find LCM of 4,15 we have to write multiple series of both the numbers. Identify common number in both. Multiples of 4: 4,8,12,16,20,24,28,32,36,40,45,58,52,56, 60 ,64......... Multiples of 15: 15,30,45, 60 ,75.......... we can say 60 is LCM of 4,15 but this takes more time. I

Prime factorization

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Prime factorization is a method of representing a number in terms of multiples of prime numbers which is more powerful in identifying co-primes, LCM, HCF, number of its factors. What are prime numbers? These are the numbers which have no factors other than one and itself. Divide and rule was

Numbers and number systems

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In this post let us clearly know about the classification of the number system.before classifying numbers let us know about numbers and number systems.  what is a number? =>A number can be defined as a group of digits which have some value. what is a number system? =>The systematic way in which numbers are organized

Rivers Boats and streams

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In Boats and stream based problems,we need to calculate either speed or time to reach some point either upstream or downstream. In water,the direction of the flow is downstream and opposite direction is upstream.

Work time efficiency based problem tips

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One of the important topics in aptitude solving is work-time-efficiency based problems but we should be able to manage time which is possible by solving more and more problems. Important points to remember: If A can finish work in m minutes and B can finish the same work in n minutes then both

Partnership based problems

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Two or more people doing business with the shared pool of resources and shared return on investment refers to Partnership and the one who invested can be considered as a partner. There are many types of partners: Active partner: The partner who manages the business. Sleeping partner: The partner who just invests and doesn't work.

Age based probems and tips

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Aptitude solving also comprises of few problems based on age calculation, they are normal but the sentences used there makes it look as if it is complex. The main parts of Age based problems are  Present age

Clock Based tips

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Aptitude problems based on clocks can be generally 2 types Angle based problems Incorrect clocks Basic rules: For Angle based problems : Every hour, Hour hand and minute hand co-incides only once

Recurring decimal tricks

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Here are few tricks for Recurring decimals........... Recurrence can be defined as reoccurrence of same thing. to solve recurring decimals problems,we need to follow few basics. Trick 1:(0.ab....) Let N be a number with 'n' digits in it , and M be another 'n' digit number which has all 9's then  N/M produces a number 0.NNNNNNNNN.................... e.x: 12/99=0.1212........ e.x:1234/99999=0.12341234.......... e.x: 8567/9999=0.85678567........ Trick 2:(0.abbb...........)  0.abbbbbbbb.........  is equivalent to (ab-a)/90

Calendar problems solving tips without any formula

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If you keenly observe the calendar, if today is Wednesday same date of the next year will be Thursday (if there is no Feb 29 in between) and Friday(if Feb 29 comes) but what if someone asks you to find the day of a given random date? I have found many people asking calendar problems formula. there is no need for any formula as you can do it all by yourself with calendar problem aptitude tricks.  So here is a simple procedure with which you can simply find the day of a given date. Before learning the complete procedure, let me introduce a few basic terms required to solve these type of problems. Calendars are prepared based on the earth's orbit around the sun and it is designed it in a way that every orbit is equivalent to 1 year. with some fraction of the day left out for a year and this fraction is adjusted with the help of leap days. Most of the people think that every 4th year is a leap year but this is not true if one considers every 4th year as a lea

Basics: Divisibility test

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Many problems in Aptitude solving can be done in seconds if you can apply these rules for divisibility test. Divisible by:                Rule 2                                   last digit is even(0,2,4,6,8) 3 -                                 sum of all the digits is divisible by 3 4                                   last 2 digits should be divisible by 4 5                                   the last digit is either 0 or 5