M4apt

Two or more people doing business with the shared pool of resources and shared return on investment refers to Partnership and the one who invested can be considered as a partner. There are many types of partners: Active partner: The partner who manages the business. Sleeping partner: The partner who just invests and doesn't work.

Aptitude solving also comprises of few problems based on age calculation, they are normal but the sentences used there makes it look as if it is complex. The main parts of Age based problems are  Present age

Aptitude problems based on clocks can be generally 2 types Angle based problems Incorrect clocks Basic rules: For Angle based problems : Every hour, Hour hand and minute hand co-incides only once

Here are few tricks for Recurring decimals........... Recurrence can be defined as reoccurrence of same thing. to solve recurring decimals problems,we need to follow few basics. Trick 1:(0.ab....) Let N be a number with 'n' digits in it , and M be another 'n' digit number which has all 9's then  N/M produces a number 0.NNNNNNNNN.................... e.x: 12/99=0.1212........ e.x:1234/99999=0.12341234.......... e.x: 8567/9999=0.85678567........ Trick 2:(0.abbb...........)  0.abbbbbbbb.........  is equivalent to (ab-a)/90

If you keenly observe the calendar, if today is Wednesday same date of the next year will be Thursday (if there is no Feb 29 in between) and Friday(if Feb 29 comes) but what if someone asks you to find the day of a given random date? I have found many people asking calendar problems formula. there is no need for any formula as you can do it all by yourself with calendar problem aptitude tricks.  So here is a simple procedure with which you can simply find the day of a given date. Before learning the complete procedure, let me introduce a few basic terms required to solve these type of problems. Calendars are prepared based on the earth's orbit around the sun and it is designed it in a way that every orbit is equivalent to 1 year. with some fraction of the day left out for a year and this fraction is adjusted with the help of leap days. Most of the people think that every 4th year is a leap year but this is not true if one considers every 4th yea...

Many problems in Aptitude solving can be done in seconds if you can apply these rules for divisibility test. Divisible by:                Rule 2                                   last digit is even(0,2,4,6,8) 3 -                                 sum of all the digits is divisible by 3 4                                   last 2 digits should be divisible by 4 5                                   the last digit is either 0 or 5