M4apt

Here are few tricks for Recurring decimals........... Recurrence can be defined as reoccurrence of same thing. to solve recurring decimals problems,we need to follow few basics. Trick 1:(0.ab....) Let N be a number with 'n' digits in it , and M be another 'n' digit number which has all 9's then  N/M produces a number 0.NNNNNNNNN.................... e.x: 12/99=0.1212........ e.x:1234/99999=0.12341234.......... e.x: 8567/9999=0.85678567........ Trick 2:(0.abbb...........)  0.abbbbbbbb.........  is equivalent to (ab-a)/90

If you keenly observe the calendar, if today is Wednesday same date of the next year will be Thursday (if there is no Feb 29 in between) and Friday(if Feb 29 comes) but what if someone asks you to find the day of a given random date? I have found many people asking calendar problems formula. there is no need for any formula as you can do it all by yourself with calendar problem aptitude tricks.  So here is a simple procedure with which you can simply find the day of a given date. Before learning the complete procedure, let me introduce a few basic terms required to solve these type of problems. Calendars are prepared based on the earth's orbit around the sun and it is designed it in a way that every orbit is equivalent to 1 year. with some fraction of the day left out for a year and this fraction is adjusted with the help of leap days. Most of the people think that every 4th year is a leap year but this is not true if one considers every 4th yea...

Well we are all aware of calculating simple interest in our regular life and perhaps many solve this on the go,even though this post is for some one who is trying to figure out how to calculate simple interest for a loan lend or borrowed. Terms: Simple Interest(SI):Cash to be paid for using other's money. Principal(P): Amount lend or Amount borrowed.

Ratios and proportions is one of the most important topic in aptitude because of wide range of it's applications like ages, percentages, mixtures and allegations... Ratio is a quantitative relation between two or more numbers which tells how many times one number is w.r.t other. If a certain amount N is divided among A, B in a ratio a:b then A's share is a/(a+b) * N and B's share is b/(a+b) *N If A:B = a:b and B:C = c:d then A:C = a*c : b*d If A:B = p:q, B:C = r:s, C:D = t:u then A:D = A/D = (A/B) * (B/C) * (C/D)   If a quantity is increased by a/b then the new content becomes (a+b)/b If a quantity is decreased by a/b then the new content becomes (b-a)/b To reduce your computations, it is always recommended to remember these values in terms of percentages 1/1 = 100 % 1/2 = 50 % 1/3 = 33.33 % 1/4 = 25 % 1/5 = 20 % 1/6 = 16.66 % 1/7 = 14.28 %       1/13 = 7.6% 1/8 = 12.25 %       1/12 = 8.33% 1/9 = 11.11 %       1...

Aptitude solving also comprises of few problems based on age calculation, they are normal but the sentences used there makes it look as if it is complex. The main parts of Age based problems are  Present age

Solving aptitude and trying to do fast math? you are here at the correct place then. this post enables you to solve square of a number within a few seconds when results are observed practically, the average time taken to find squares of 10 random numbers is 103 seconds. Before going into the topic, let me tell my experience, it was a typical day in our college and that was a boring lecture and all the students were busy trying to listen the class, there begins the actual story my friend who is aiming to crack the CAT exam and get a seat in one of the reputed MBA school was doing some rough work at the end of his notes. he then told me the importance of fast math in the competitive exams and how it reduces the solving time from minutes to seconds in many cases. being curious about the fast math, I have searched a lot to find the squares of the numbers and found many techniques after watching youtube videos, referring some books, blogs... but it was a big question mark w...

After investing some time in the preparation, it's not uncommon to realize that it would be better if we make our own notes which we can refer while revising these topics before the exam. In order to make this procedure simple, I have come up with this post. 1) Ratios and proportions: If a certain amount N is divided among A, B in a ratio a:b then A's share is a/(a+b) * N and B's share is b/(a+b) *N If A:B = a:b and B:C = c:d then A:C = a*c : b*d If A:B = p:q, B:C = r:s, C:D = t:u then A:D = A/D = (A/B) * (B/C) * (C/D)    If a quantity is increased by a/b then the new content becomes (a+b)/b If a quantity is decreased by a/b then the new content becomes (b-a)/b To reduce your computations, it is always recommended to remember these values in terms of percentages 1/1 = 100 % 1/2 = 50 % 1/3 = 33.33 %   1/4 = 25 % 1/5 = 20 % 1/6 = 16.66 % 1/7 = 14.28 %       1/13 = 7.6% 1/8 = 12.25 %       1/12 = 8.33% 1/9 = 11.11 % ...

Voila, you are here! Problems on trains in aptitude problems are not just to test your ability to solve the problems on trains and their properties but you can logically resolve many theories using this concept and this is one of the important part while learning aptitude. Conversions: A Kilometer/Hour = A(5//18) meter/second. A meter/second = A(18/5) Kilometer/Hour. Foundation: Time taken by a train of length 'l' units to cross a fixed point or pole is equal to the time taken by the train to travel 'l' units. Time taken by a train of length 'l' units to cross a  stationery object of length 'm' units units is equal to the time taken by the train to travel 'l+m' units. Suppose 2 trains are moving in the same direction with speeds U , V where U > V then their relative speed is U - V .